24=-0.05x^2+2.2x+7

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Solution for 24=-0.05x^2+2.2x+7 equation:



24=-0.05x^2+2.2x+7
We move all terms to the left:
24-(-0.05x^2+2.2x+7)=0
We get rid of parentheses
0.05x^2-2.2x-7+24=0
We add all the numbers together, and all the variables
0.05x^2-2.2x+17=0
a = 0.05; b = -2.2; c = +17;
Δ = b2-4ac
Δ = -2.22-4·0.05·17
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.2)-\sqrt{1.44}}{2*0.05}=\frac{2.2-\sqrt{1.44}}{0.1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.2)+\sqrt{1.44}}{2*0.05}=\frac{2.2+\sqrt{1.44}}{0.1} $

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